Finding the distance between two points

 
 
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How to build the distance formula from the Pythagorean Theorem

In this lesson you’ll learn how to use the distance formula to calculate the distance between two points.

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graph of two points in coordinate space
 

Let’s begin by looking at two points on a graph. The distance formula will calculate the length of the straight line between the two points.

 
graph of the line connecting the two points
 

You can draw a right triangle that has the line between these two points as its hypotenuse.

 
graph of the right triangle formed using the distance as the hypotenuse
 

We can find the lengths of the sides,

 
graph showing the side lengths of the right triangle
 

and use the Pythagorean theorem, ???a^2+b^2=c^2???, to find the length between the original two points.

???4^2+4^2=c^2???

???32=c^2???

???c=\sqrt{32}???

???c=\sqrt{16\cdot 2}???

???c=\sqrt{16}\cdot\sqrt{2}???

???c=4\sqrt2???

 
using the pythagorean theorem to find the distance between the points
 

So what did we do to get the length between the two points? If we just rearrange what we did with the Pythagorean theorem, we get

???c=\sqrt{(5-1)^2+(-1-3)^2}???

or in other words,

???c=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}???

And that’s the distance formula! Only the distance formula uses ???d??? instead of ???c???. It says that the distance between two points ???(x_1,y_1)??? and ???(x_2,y_2)??? is

???d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}???

 
 

How to use the Pythagorean Theorem to calculate the distance between two points in coordinate space


 
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Using the distance formula to find the distance between two points

Example

What is the distance between the two points?

???(5,7)???

???(-3,5)???

We’ll plug the given points ???(x_1,y_1)=(5,7)??? and ???(x_2,y_2)=(-3,5)??? into the distance formula.

???d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}???

???d=\sqrt{(-3-5)^2+(5-7)^2}???

???d=\sqrt{(-8)^2+(-2)^2}???

???d=\sqrt{64+4}???

???d=\sqrt{68}???

???d=\sqrt{4 \cdot 17}???

???d=\sqrt{4}\cdot \sqrt{17}???

???d=2\sqrt{17}???


The distance formula works with irrational numbers as well.


Distance between two points for Algebra 2.jpg

You can draw a right triangle that has the line between these two points as its hypotenuse.

Example

Find the distance between the points.

???(3,\sqrt{2})???

???(2,-\sqrt{2})???

We’ll plug the given points ???(x_1,y_1)=(3,\sqrt{2})??? and ???(x_2,y_2)=(2,-\sqrt{2})??? into the distance formula.

???d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}???

???d=\sqrt{(2-3)^2+\left(\sqrt{2}-(-\sqrt{2})\right)^2}???

???d=\sqrt{(2-3)^2+(\sqrt{2}+\sqrt{2})^2}???

???d=\sqrt{(-1)^2+(2\sqrt{2})^2}???

???d=\sqrt{1+2^2 \cdot (\sqrt{2})^2}???

???d=\sqrt{1+4 \cdot 2}???

???d=\sqrt{1+8}???

???d=\sqrt{9}???

???d=3???

 
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