What is the Understood 1?

 
 
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What happens when you multiply by 1?

What happens when you multiply or divide something by 11, or raise something to the first power? It stays the same. This is the premise of the “understood 11.”

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When you have a variable such as xx, you should get to a point where you almost immediately remember that “just plain xx” can be written as 1x1x, because x=1x=1xx=1\cdot x=1x, and similarly that xx can be written as x/1x/1 or x1x^1.

Cases of the Understood 11:

x=1xx=1\cdot x

x=1xx=1x

x=x1x=\frac{x}{1}

x=x1x=x^1

If we combine the kinds of techniques that we used to get these expression, we can also say

x=1x11x=\frac{1x^1}{1}

Why is this useful? There are times when xx appears in a fraction, or xx is added to some term in which xx appears, or xx is multiplied by some factor in which xx appears. When something like this happens, it’ll be helpful to remember the understood 11 (and maybe even write out a 11 instead of leaving it as an understood 11).

 
 

Applying the understood 1 as a coefficient, an exponent, and a denominator


 
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How to use the idea of the understood 1 to simplify expressions

Example

Simplify the expression.

(x+2x)x3(x +2x) \cdot x^3


Start by simplifying parentheses and remember that x=1xx=1x.

(1x+2x)x3(1x+2x)\cdot x^3

(3x)x3(3x)\cdot x^3

Multiply and remember that 3x=3x13x=3x^1.

3x1x33x^1\cdot x^3

3x43x^4


This time let’s go in the opposite direction, by looking at an example where one or more “unnecessary” 11’s appear in an expression that we can simplify by replacing the unnecessary 11’s with understood 11’s.


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“just plain x” can be written as 1x, or as x/1, or as x^1.

Example

Simplify the expression.

11(1x1)+1(x1+1)\frac{1}{1(1x^1)}+1\left(\frac{x}{1}+1\right)

In this example the understood 11 has been written out multiple times. Let’s simplify by removing the understood 11.

11x1+1(x1+1)\frac{1}{1x^1}+1\left(\frac{x}{1}+1\right)

1x1+1(x1+1)\frac{1}{x^1}+1\left(\frac{x}{1}+1\right)

1x+1(x1+1)\frac{1}{x}+1\left(\frac{x}{1}+1\right)

1x+x1+1\frac{1}{x}+\frac{x}{1}+1

1x+x+1\frac{1}{x}+x+1


In our next example, we’ll see how to deal with the understood 11 when we want to add two fractions where the denominator of one fraction is just plain xx and the denominator of the other fraction is xx raised to some power other than 11.


Example

Add the fractions.

2x+5x3\frac{2}{x}+\frac{5}{x^3}

In the denominator of the first fraction, use the fact that x=x1x=x^1.

2x1+5x3\frac{2}{x^1}+\frac{5}{x^3}

If we multiply the top and bottom of the first fraction by x2x^2, we’ll find that we can use x3x^3 as the common denominator.

2x1(x2x2)+5x3\frac{2}{x^1}\left(\frac{x^2}{x^2}\right)+\frac{5}{x^3}

2(x2)x1(x2)+5x3\frac{2(x^2)}{x^1(x^2)}+\frac{5}{x^3}

2x2x3+5x3\frac{2x^2}{x^3}+\frac{5}{x^3}

2x2+5x3\frac{2x^2+5}{x^3}


 
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